petit probleme pour charger mon doc xml

petit probleme pour charger mon doc xml - Programmation

Marsh Posté le 21-08-2002 à 10:14:57    

voila g regarder le tuito sur l'utilisation du XML dans PHP (http://www.phpbuilder.com/columns/matt20001228.php3)
mais j'ai des pb avec php y'a as de messsage d'erreur mais en sortie j'ai :  
the , employee
the , employee
the , employee
 
sinon voila le code php :

Code :
  1. <?php
  3. # iterate through an array of nodes
  4. # looking for a text node
  5. # return its content
  6. function get_content($parent)
  7. {
  8.     $nodes = $parent->children();
  9.     while($node = array_shift($nodes))
  10.         if ($node->type == XML_TEXT_NODE)
  11.             return $node->content;
  12.     return "";
  13. }
  15. # get the content of a particular node
  16. function find_content($parent,$name)
  17. {
  18.     $nodes = $parent->children();
  19.     while($node = array_shift($nodes))
  20.         if ($node->name == $name)
  21.             return get_content($node);
  22.     return "";
  23. }
  25. # get an attribute from a particular node
  26. function find_attr($parent,$name,$attr)
  27. {
  28.     $nodes = $parent->children();
  29.     while($node = array_shift($nodes))
  30.         if ($node->name == $name)
  31.             return $node->getattr($attr);
  32.     return "";
  33. }
  35. # load xml doc
  36. $doc = xmldocfile('c:\employ.xml') or die ("erreur ne trouve pas le fichier" );
  38. # get root Node (employees)
  39. $root = $doc->root();
  41. # get an array of employees' children
  42. # that is each employee node
  43. $employees = $root->children();
  45. # shift through the array
  46. # and print out some employee data
  47. while($employee = array_shift($employees))
  48. {
  49.     if ($employee->type == XML_TEXT_NODE)
  50.         continue;
  52.     $name = find_content($employee,"name" );
  53.     $pos = find_content($employee,"position" );
  54.     $type = find_attr($employee,"position","type" );
  56.     echo $name." the ".$pos.", ".$type." employee<br>";
  57. }
  59. ?>


 
et le xml  

Code :
  1. <?xml version="1.0"?>
  3. <employees company="zoomedia.com">
  4. <employee>
  5.  <name>Matt</name>
  6.  <position type="contract">Web Guy</position>
  7. </employee>
  9. <employee>
  10.  <name>George</name>
  11.  <position type="full time">Mad Hacker</position>
  12. </employee>
  14. <employee>
  15.  <name>Wookie</name>
  16.  <position type="part time">Hairy SysAdmin</position>
  17. </employee>
  18. </employees>


 
qq'un aurait une idee

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Marsh Posté le 21-08-2002 à 10:14:57   

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